Is it possible in kotlin serialization without using intermediate options to immediately convert Map <String, Any> to a model

Issue

This case is in the JS version (Properties.decodeFromMap (map)), but for android, I have not seen.

It can also be solved using Jackson

The object in which I should get a rather complex type, the approximate form of the fields is much larger

data class BaseModel (val value: String,val options: Options,val type: Type ...)

The main thing I need to get directly from Map <String, Any> in BaseModel

Solution

I think it's better to use the properties from the kotlinx-serialization-properties package, it turns out that it is also distributed for android

Answered By - Divider