How to pick every time new or unique random item from a array list in android?

Issue

I need to pick a new item from a list that hasn't been picked already until there are no more.

Here is my code:

private var quizQuestionList: ArrayList<Quiz> 
private var pickedItems: ArrayList<Int>
private var random: Random = Random()

private fun pickItem(): Quiz {
    var index = random?.nextInt(quizQuestionList!!.size)

    if (pickedItems.contains(index)) {
        index = random?.nextInt(quizQuestionList!!.size)
        pickedItems.add(index)
    } else {
        pickedItems.add(index)
    }

    val item = quizQuestionList!!.get(index!!)
    return item
}

Please suggest any solution that gives me a new item every time. I used an int list for all previously picked items and check every time when picked new item but I didn't get success.

Solution

It isn't obvious what you are looking for, but it looks like you want to show different Quiz question from ArrayList. In condition of, when that question is shown, no more same question will be shown. Here is how you should do, I will give you just the logic you could try it yourself:

import java.util.Random

fun main(args: Array<String>) {

    val random = Random()
    var randomInt: Int
    var pickedInt: MutableSet<Int> = mutableSetOf()

    fun rand(from: Int, to: Int): Int{
        do{
            randomInt = random.nextInt(to - from) + from
        }while(pickedInt.contains(randomInt))

        pickedInt.add(randomInt)
        return randomInt
    }

    while(pickedInt.size < 9){
        var differentNumber = rand(1,11)
        println(differentNumber)
    }
}

This will print nine different Number. The way I choosing MutableSet is because it will only have unique values, no duplicated value. Hope it helps!

Answered By - willy wijaya