Issue
Hello i just started a coding exercise on hackerrank and i am having a little challenge using scanner class with the skip function. here is what i have tried. Objective In this challenge, we're getting started with conditional statements. Check out the Tutorial tab for learning materials and an instructional video!
Task
Given an integer, perform the following conditional actions:
- If n is odd, print Weird
- If n is even and in the inclusive range of 2 to 5, print Not Weird
- If n is even and in the inclusive range of 6 to 20, print Weird
- If n is even and greater than 20, print Not Weird
- Complete the stub code provided in your editor to print whether or not n is weird.
Input Format
A single line containing a positive integer,n.
Constraints
Output Format
Print Weird if the number is weird; otherwise, print Not Weird.
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class Solution {
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
int N = scanner.nextInt();
if (N % 2 == 0 && N >= 2 && N <= 5 && N > 20) {
System.out.println("not weird");
} else if (N % 2 == 0 && N >= 6 && N <= 20) {
System.out.println("weird");
} else {
System.out.println("weird");
}
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
scanner.close();
}
}
Please what am i doing wrong.
Solution
You're mixing up &&
and ||
, so your first if
will never run as mentioned in the comments.
So it looks like the only "Not Weird"
print out is 2
, 4
and even numbers > 20
.
So use this to your advantage to just check for the "Weird"
outputs, otherwise print "Not Weird"
.
if (n % 2 == 0) {
if ((n >= 2 && n <= 5) || (n > 20)) {
return "Not Weird";
}
}
return "Weird";
Having said this, I'm not sure what you want with Scanner::skip
Answered By - achAmháin
0 comments:
Post a Comment
Note: Only a member of this blog may post a comment.