Calling super method from interface

Issue

I want to call a super method from overriden method with the same name from an interface thats extending another interface

Example:

    default private interface A {
        void foo() {
            System.out.println("B");
        }
    }

    private interface B extends A {
        @Override
        default void foo() {
            System.out.println("B");
        }
    }

I want to call classC(implements interface B).foo() ending with output

B
A.foo() call

How can i achive this?

In my case i dont want to implement interface B, because it's a interface thats extending JpaRepository, and I'm just calling repository methods using only this interface.

UPDATE:

I gave the wrong example, thats not describing my problem. Below is the description of my specific problem.

Before saving object to db i want to make some actoions on this object. I'm using interface repositories. I want to override a Repository.save(Object o) method, and make changes there, but im just not able to call a super method from extended repository.

Example:

public interface FooRepository extends MongoRepository<Foo, String> {

    @Override
    default <S extends Foo> S save(S s) {
        s.doSth();
        return MongoRepository.super.save(s);   //This doesn't compile
    }
}

I know i can do this by creating the class and injecting FooRepository in there, but is there any way to do this by overriding a save() method in FooRepository?

Solution

In B interface in method foo() you can call A.foo() such way:

    @Override
    default void foo() {
        System.out.println("B");
        A.super.foo();
    }

Answered By - Cookie