Issue
I have an example of an xml I want to parse
<?xml version="1.0" encoding="utf-8"?>
<Details>
<detail-a>
<detail> attribute 1 of detail a </detail>
<detail> attribute 2 of detail a </detail>
<detail> attribute 3 of detail a </detail>
</detail-a>
<detail-b>
<detail> attribute 1 of detail b </detail>
<detail> attribute 2 of detail b </detail>
</detail-b>
</Details>
I would like from this xml to write a method that will parse it to hashmap that the key is a string and the value is a list of strings.
for instance : key "detail a" value={"attribute 1 of detail a","attribute 2 of detail a","attribute 3 of detail a"}
and so on..
what is the best way to do this ? because I got confused :\
I got this far to try to print detail-a and detail-b but I get blank...
public static void main(String[] args) {
// TODO Auto-generated method stub
DocumentBuilderFactory factory=DocumentBuilderFactory.newInstance();
DocumentBuilder builder;
try {
builder = factory.newDocumentBuilder();
File f= new File("src/Details.xml");
Document doc=builder.parse(f);
Element root=doc.getDocumentElement();
NodeList children=root.getChildNodes();
for(int i=0;i<children.getLength();i++)
{
Node child=children.item(i);
if (child instanceof Element)
{
Element childElement=(Element) child;
Text textNode=(Text)childElement.getFirstChild();
String text=textNode.getData().trim();
System.out.println(text);
}
}
} catch (ParserConfigurationException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Solution
Use JAXB
to read from xml
and save it to a custom object.
Custom object class:
import java.util.List;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
@XmlRootElement(name = "Details")
@XmlType(propOrder = { "detailA", "detailB" })
public class Details {
private List<String> detailA;
private List<String> detailB;
public void setDetailA(List<String> detailA) {
this.detailA = detailA;
}
@XmlElementWrapper(name = "detail-a")
@XmlElement(name = "detail")
public List<String> getDetailA() {
return detailA;
}
public void setDetailB(List<String> detailB) {
this.detailB = detailB;
}
@XmlElementWrapper(name = "detail-b")
@XmlElement(name = "detail")
public List<String> getDetailB() {
return detailB;
}
}
Extract the data from your xml into the object, then add contents to a map as desired:
public static void main(String[] args) throws JAXBException, FileNotFoundException {
System.out.println("Output from our XML File: ");
JAXBContext context = JAXBContext.newInstance(Details.class);
Unmarshaller um = context.createUnmarshaller();
Details details = (Details)um.unmarshal(new FileReader("details.xml"));
List<String> detailA = details.getDetailA();
List<String> detailB = details.getDetailB();
Map<String, String[]> map = new HashMap<String, String[]>();
map.put("detail-a", detailA.toArray(new String[detailA.size()]));
map.put("detail-b", detailB.toArray(new String[detailB.size()]));
for (Map.Entry<String, String[]> entry : map.entrySet()) {
//key "detail a" value={"attribute 1 of detail a","attribute 2 of detail a","attribute 3 of detail a"}
System.out.print("Key \"" +entry.getKey()+"\" value={");
for(int i=0;i<entry.getValue().length;i++){
if(i!=entry.getValue().length-1){
System.out.print("\""+entry.getValue()[i]+"\",");
}
else{
System.out.print("\""+entry.getValue()[i]+"\"}");
}
}
System.out.println();
}
}
Output will be:
Output from our XML File: Key "detail-a" value={"attribute 1 of detail a","attribute 2 of detail a","attribute 3 of detail a"} Key "detail-b" value={"attribute 1 of detail b","attribute 2 of detail b"}
As a note: this will work only for the xml you provided as input in your question, if you need to add more details like detail-c
and so on you must define them in your custom object as well.
XML used:
<?xml version="1.0" encoding="utf-8"?>
<Details>
<detail-a>
<detail>attribute 1 of detail a</detail>
<detail>attribute 2 of detail a</detail>
<detail>attribute 3 of detail a</detail>
</detail-a>
<detail-b>
<detail>attribute 1 of detail b</detail>
<detail>attribute 2 of detail b</detail>
</detail-b>
</Details>
Answered By - MihaiC
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