Issue
In my flutter app, I have a future that handles http requests and returns the decoded data. But I want to be able to send an error if the status code != 200
that can be gotten with the .catchError()
handler.
Heres the future:
Future<List> getEvents(String customerID) async {
var response = await http.get(
Uri.encodeFull(...)
);
if (response.statusCode == 200){
return jsonDecode(response.body);
}else{
// I want to return error here
}
}
and when I call this function, I want to be able to get the error like:
getEvents(customerID)
.then(
...
).catchError(
(error) => print(error)
);
Solution
You can use throw
:
Future<List> getEvents(String customerID) async {
var response = await http.get(
Uri.encodeFull(...)
);
if (response.statusCode == 200){
return jsonDecode(response.body);
}else{
// I want to return error here
throw("some arbitrary error"); // error thrown
}
}
Answered By - anmol.majhail
0 comments:
Post a Comment
Note: Only a member of this blog may post a comment.