Issue
Please does anyone know how to catch firebase Auth exceptions on flutter and display them?
Note: I am not interested in the console (catcherror((e) print(e))
I need something that is more effective, e.g " user doesn't exist" So that I can then pass it to a string and display it.
Been dealing with this for months.
Thanks in advance.
I have tried replacing print(e) with // errorMessage=e.toString(); and then passing it to a function, all efforts have been futile.
FirebaseAuth.instance
.signInWithEmailAndPassword(email: emailController.text, password: passwordController.text)
.then((FirebaseUser user) {
_isInAsyncCall=false;
Navigator.of(context).pushReplacementNamed("/TheNextPage");
}).catchError((e) {
// errorMessage=e.toString();
print(e);
_showDialog(errorMessage);
//exceptionNotice();
//print(e);
I want to be able to extract the exception message and pass the exception message to a dialog that I can then display to the user.
Solution
(21/02/20) EDIT: This answer is old and the other answers contains cross platform solutions so you should look at theirs first and treat this as a fallback solution.
The firebase auth plugin doesn't really have a proper cross-platform error code system yet so you have to handle errors for android and ios independently.
I'm currently using the temporary fix from this github issue: #20223
Do note since its a temp fix, don't expect it to be fully reliable as a permanent solution.
enum authProblems { UserNotFound, PasswordNotValid, NetworkError }
try {
FirebaseUser user = await FirebaseAuth.instance.signInWithEmailAndPassword(
email: email,
password: password,
);
} catch (e) {
authProblems errorType;
if (Platform.isAndroid) {
switch (e.message) {
case 'There is no user record corresponding to this identifier. The user may have been deleted.':
errorType = authProblems.UserNotFound;
break;
case 'The password is invalid or the user does not have a password.':
errorType = authProblems.PasswordNotValid;
break;
case 'A network error (such as timeout, interrupted connection or unreachable host) has occurred.':
errorType = authProblems.NetworkError;
break;
// ...
default:
print('Case ${e.message} is not yet implemented');
}
} else if (Platform.isIOS) {
switch (e.code) {
case 'Error 17011':
errorType = authProblems.UserNotFound;
break;
case 'Error 17009':
errorType = authProblems.PasswordNotValid;
break;
case 'Error 17020':
errorType = authProblems.NetworkError;
break;
// ...
default:
print('Case ${e.message} is not yet implemented');
}
}
print('The error is $errorType');
}
Answered By - Swift
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