Simple java input Strings

Issue

import java.io.*;

public class ManyTickets
 {

  public static void main (String [] args) throws IOException
  {
   String userInput;
   String userInput2;
   int intInput = 0;
   int intInput2 = 0;
   double total = 0.00;
   //(1) BufferedReader ageInput = new BufferedReader (new InputStreamReader (System.in));

Question 1: Above line works fine (1) when we change it into other place which i marked as (2). // but while executing "Please enter your age"line comes first though i create bufferedreader object before that statement in case (1).I expect compiler should wait for user input but it prints the statement. Though i create ageInput before try.

try{
    System.out.println("Please enter your age, or press '999' to exit.");

   //(2) BufferedReader ageInput = new BufferedReader (new InputStreamReader (System.in));

    userInput = ageInput.readLine();
    intInput = Integer.parseInt (userInput);
    while (intInput != 999)

//Question2:While executing by 999 if i type 999 without giving space it is execute it gives some output but not exit.how to avoid whitespaces in the beginning like whatever i am giving whether 999 or 999 or999 i need same output.I need exit but not for input like 99 9; I need method to avoid whitespaces in the input(beginning).

{
     if (intInput < 0 || intInput > 110)
     System.out.println("Invalid entry, or your age seems a bit too high to enter buy
     tickets);
     else if (intInput <= 12)
     {
      total = total + 6;
      System.out.println("The ticket cost for 1 ticket is " + total);
     }
      else if (intInput <= 64)
     {
      total = total + 11;
      System.out.println("The ticket cost for 1 ticket is " + total);  
      }
       else
      {
       total = total + 8;
       System.out.println("The ticket cost for 1 ticket is $" + total);
       }
       System.out.println("So far, your tickets cost is: $" + total  );
       System.out.print("Would you like to buy more tickets? You can buy up to 1 more ticket    per customer! If no press 999to exit");
       userInput = ageInput.readLine();
       intInput2 = Integer.parseInt (userInput);  
        }
       }catch (NumberFormatException e){
       System.out.println("Please restart the program, and enter an integer instead!");
        }
        } 
       {
        double total = 0.0;
        System.out.println("Thank you,  The total cost for the ticket is: $" + total);
        System.out.println("Have a nice day!");
       }
       }

Solution

Question2:While executing by 999 if i type 999 without giving space it is execute it gives some output .how to avoid whitespaces in the beginning like whatever i am giving whether 999 or 999 i need same output. I need method to avoid whitespaces in the input.

To avoid white spaces simply remove them from strings like following:

userInput = ageInput.readLine().replaceAll(" ","");
intInput = Integer.parseInt (userInput);

Question 1: Above line works fine (1) when we change it into other place which i marked as (2). // but while executing "Please enter your age"line comes first though i create bufferedreader object before that statement in case (1).I expect compiler should wait for user input but it prints the statement. Though i create ageInput before try.

This is too ambiguous.

Answered By - Darshan Lila