Issue
I was following a tutorial when I stumbled on something I couldn't quite wrap my head around. This is the drawable resource that I use as the source for an image button.
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape
android:shape="rectangle">
<stroke android:width="2dp"
android:color="@color/light_silver"/>
<padding android:bottom="0dp"
android:left="0dp"
android:right="0dp"
android:top="0dp"/>
</shape>
</item>
<item>
<shape android:shape="rectangle">
<stroke android:width="2dp"
android:color="@color/light_silver"/>
<solid android:color="#00000000"/>
<corners android:radius="10dp"/>
</shape>
</item>
</layer-list>
And this is the ImageButton
.
<ImageButton
android:layout_height="25dp"
android:layout_width="25dp"
android:layout_margin="2dp"
android:src="@drawable/pallet_normal"
android:background="@color/yellow"
android:tag="@color/yellow"/>
and this is the result that is created from this.
I don't understand why the background is overlapping the drawable resource. Isn't the middle of the drawable supposed to be black as that's what I set in the solid tag? Please help, I am very confused.
Solution
You use a transparent color by setting the alpha channel to 00
which made the color full transparent; to make it full opaque, you can set it to ff
>> <solid android:color="#ff000000"/>
or remove the alpha channel by only using 6-digit color >> <solid android:color="#000000"/>
.
For extra help about using the alpha digits in android, pls check out this question.
Answered By - Zain
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