tricky Android Google Map zoom while maintaining center point

Issue

It's not easy explaining my problem but I will try.

I have an android GoogleMap, on top of it, I have an ImageView positioned at its center at all times. If I drag/pan the map, the pin will always be in the center of the GoogleMap.

Now, I add a marker, somewhere on the map. I want to zoom such that the center point remains in the center of the map, and the marker is visible within the map, and to the highest zoom level.

The problem is if I simply check if the marker is within boundaries of the map or not, and then keep zooming in/out till it is, this process will always repeat itself, i.e. trying to zoom in and if the marker became outside, then zoom out.

The problem is I rely on an OnCameraChange listener which will keep calling itself everytime I zoom in or out, hence, the process of zooming in/out will keep occuring indefinitely

journeyGoogleMap.setOnCameraChangeListener(new OnCameraChangeListener()
{
   @Override
   public void onCameraChange(final CameraPosition position)
   {

Basically, what I need is a function where I can provide the center LatLng and the markerLatLng and it will automatically calculate the LatLngBounds making sure my center is within the center of the LatLng bounds, and then I can simply use

public static CameraUpdate newLatLngBounds (LatLngBounds bounds, int width, int height, int padding)

as shown in the link below https://developers.google.com/maps/documentation/android/reference/com/google/android/gms/maps/CameraUpdateFactory#newLatLngBounds(com.google.android.gms.maps.model.LatLngBounds,int, int,int)

If you need anymore clarification please do tell me

Solution

You need to calculate LatLngBounds from two points:

1. Your marker position and
2. Place on the opposite side of your current center.

The second is calculated like this:

LatLng other = new LatLng(2 * center.latitude - position.latitude, 2 * center.longitude - position.longitude);

See LatLngBoundsUtils.fromCenterAndPositions for a general solution.

Answered By - MaciejGórski