Is it possible to add two numbers whose power is the iterator in for loop in Kotlin without using power function

Issue

Programming Language: KOTLIN

I'm trying to make a function which adds two numbers in the following way.. a^i+b^i where "i" would be the iterator in for loop. So I want the i to range from 1 to 10 and print the result one by one like this... for example if I give the values as a=1 & b=2 then the result must be calculated as.. a^1+b^1= 1^1+2^1 which gives 3 so print the result. a^2+b^2= 1^2+2^2 which gives 6 and print the result. etc., repeating the process until "i" becomes 10. so I tried the following code and it only prints the result of initial values.

fun main(){
    println(test(22,33))
}
fun test(a:Int,b:Int):Int{
    var result1=1
    var result2=1
    var result3=result1+result2
     for(i in 1..10){
         result1*=a
         result2*=b
         result3=a+b
         println(result3)
         }
     return result3
   }

Solution

You were only adding the parameters of your function for result3. This works though:

fun addWithIteratedPower(a: Int, b: Int) : Int {
    var resultA = 1
    var resultB = 1
    var combinedResult = 0
    for(i in 1..10){
        resultA *= a
        resultB *= b
        combinedResult = resultA + resultB
        println(combinedResult)
    }
    return combinedResult
}

And here's a test that validates it:

@Test
fun `should return final combined result`(){
    val oneAndTwoToPowerOfTenAdded = (1.0.pow(10) + 2.0.pow(10)).toInt()
    assertThat(addWithIteratedPower(1, 2)).isEqualTo(oneAndTwoToPowerOfTenAdded)
}

Answered By - LuckyMcBeast