Issue
Nest change target_temperature_f : How to use java http PUT to set the target temperature of the Nest Thermostat by android code?
Solution
You can use either HttpClient or HttpURLConnection for calling a PUT on the rest API from Android. Here is an example using HttpURLConnection.
Note: It is advised that you cache the Redirect URL per user/access token and reuse it for all subsequent calls for that user.
- Assume here that the base to start with is https://developer-api.nest.com/
If the return code from the urlconnection is a 307 (redirect), then cache the location and use that for issuing a put request. (Note the cache here indicates a global cache/ concurrentMap of some kind)
public static int setThermostatTemperatureF(int temperatureF, String base, String thermostatId, String accessToken) throws IOException { try { String tChangeUrl = String.format("%s/devices/thermostats/%s/target_temperature_f?auth=%s", base, thermostatId, accessToken); URL url = new URL(tChangeUrl); HttpsURLConnection ucon = (HttpsURLConnection) url.openConnection(); ucon.setRequestProperty("Content-Type", "application/json"); ucon.setRequestMethod("PUT"); ucon.setDoOutput(true); // Write the PUT body OutputStreamWriter writer = new OutputStreamWriter(ucon.getOutputStream()); writer.append(Integer.toString(temperatureF)); writer.flush(); int responseCode = ucon.getResponseCode(); if (responseCode == 307) { // temporary redirect // cache the URL for future uses for this User String redirectURL = ucon.getHeaderField("Location"); URI u = new URI(redirectURL); StringBuilder baseUrl = new StringBuilder(u.getScheme()) .append("://").append(u.getHost()); if (u.getPort() != 0) { baseUrl.append(":").append(u.getPort()); } baseUrl.append("/"); cache.put(accessToken, baseUrl.toString()); return setThermostatTemperatureF(temperatureF, baseUrl.toString(), thermostatId, accessToken); } else { return responseCode; } } catch (MalformedURLException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (URISyntaxException e) { e.printStackTrace(); } return -1;
}
Answered By - Nagesh Susarla
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