Open a resource file just with specific String variable

Issue

Sorry for the title, had troubles describing what I'm trying to do. I've always had this question for Java as a whole, but right now, its specific for Android. Let's say that I am parsing an API and get this special String, let's say "clear". Inside my drawables, I have a clear.jpg that I would like to set as an ImageView programically . That's not the hard part. What I was wondering is if there was a quick way where I Could call on the .jpg with just the variable name? I know I can easily make different if statements, such as:

if(string == "clear")
{
    //setImageView to drawable/clear
}

but is there anyway I can do something such as

//setImageView to drawable/string

where string would be clear? I know obviously it would look for a string inside drawable, but is there anyway I could do what I'm describing? Just a general question I had; it was something I always wondered about.

Let me know! Thanks!

Solution

private void showImage() {
    String uri = "drawable/icon";

    // int imageResource = R.drawable.icon;
    int imageResource = getResources().getIdentifier(uri, null, getPackageName());

    ImageView imageView = (ImageView) findViewById(R.id.myImageView);
    Drawable image = getResources().getDrawable(imageResource);
    imageView.setImageDrawable(image);
}

Else I would recommend you to work with R.* references like this:

int imageResource = R.drawable.icon;
  Drawable image = getResources().getDrawable(imageResource);

Reference -> Android - Open resource from @drawable String

Answered By - Techidiot