Get Uri from file in either assets or res/raw

Issue

I have tried to get this working and I have looked at many different resources online (as you can see from all of the comments I have made). I want to access a .pdf file that is either located in assets or res; It does not matter to which one so the easiest way will do.

I have the method below that will get the actual file and will call another method(under the first method below) with the Uri in the parameters.

Thank you very much for your help and I will be standing by to answer questions or add more content.

private void showDocument(File file)
{
    //////////// ORIGINAL ////////////////////
    //showDocument(Uri.fromFile(file));
    //////////////////////////////////////////

    // try 1
    //File file = new File("file:///android_asset/RELATIVEPATH");

    // try 2
    //Resources resources = this.getResources();

    // try 4
    String PLACEHOLDER= "file:///android_asset/example.pdf";
    File f = new File(PLACEHOLDER);

    //File f = new File("android.resource://res/raw/slides1/example.pdf");

    //getResources().openRawResource(R.raw.example);

    // try 3
    //Resources resources = this.getResources();
    //showDocument(Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE + "://" + resources.getResourcePackageName(R.raw.example) + '/' + resources.getResourceTypeName(R.raw.example) + '/' + resources.getResourceEntryName(R.raw.example)));

    showDocument(Uri.fromFile(f));
}

protected abstract void showDocument(Uri uri);

Solution

from link & Get URI of .mp3 file stored in res/raw folder in android

sing the resource id, the format is:

"android.resource://[package]/[res id]"

Uri path = Uri.parse("android.resource://com.androidbook.samplevideo/" + R.raw.myvideo);

or, using the resource subdirectory (type) and resource name (filename without extension), the format is:

"android.resource://[package]/[res type]/[res name]"

Uri path = Uri.parse("android.resource://com.androidbook.samplevideo/raw/myvideo");

Answered By - Dheeresh Singh